Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 96
... zero , but , in any event , it is the only component that can be different from zero at the surface . ) Now let us apply Gauss ' law ( 4-1 ) to an arbitrary closed surface that is completely in the interior of a conductor such as S ...
... zero , but , in any event , it is the only component that can be different from zero at the surface . ) Now let us apply Gauss ' law ( 4-1 ) to an arbitrary closed surface that is completely in the interior of a conductor such as S ...
Page 212
... zero . On the other hand , if ẞ is negative , b2 ( ß ) must be zero . In both cases , the remaining term will vary as e - Bly , so that there is really only one possible form . For definiteness , we choose ẞ > 0 ; thus we must have b1 ...
... zero . On the other hand , if ẞ is negative , b2 ( ß ) must be zero . In both cases , the remaining term will vary as e - Bly , so that there is really only one possible form . For definiteness , we choose ẞ > 0 ; thus we must have b1 ...
Page 217
... zero , that is , if all of the C , are zero . We can easily show that this is the case . In ( 11-103 ) , we let cos @ = μ , multiply through by P ( u ) du , integrate over μ from 1 to +1 , and use ( 11-102 ) ; in this way we get Ž CS ...
... zero , that is , if all of the C , are zero . We can easily show that this is the case . In ( 11-103 ) , we let cos @ = μ , multiply through by P ( u ) du , integrate over μ from 1 to +1 , and use ( 11-102 ) ; in this way we get Ž CS ...
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Ampère's law angle assume axis becomes bound charge boundary conditions bounding surface calculate capacitance capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density curve cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point flux force free charge free currents frequency function given induction infinitely long integral integrand k₂ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector potential difference quadrupole quantities radiation radius rectangular region result satisfy scalar scalar potential shown in Figure solenoid sphere spherical tangential components unit vacuum vector potential velocity volume write written xy plane zero Απερ дх Мо