Mechanics of Materials |
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Page 123
... applying Eq . 4-1 ( or Eq . 4-2 ) . Since Hooke's law has been used in the development of these equations , it is important that the external loads do not cause yielding of the material and that the material is homogeneous and behaves ...
... applying Eq . 4-1 ( or Eq . 4-2 ) . Since Hooke's law has been used in the development of these equations , it is important that the external loads do not cause yielding of the material and that the material is homogeneous and behaves ...
Page 226
... Applying Eq . 5-18 gives T T = Tavg 2tAm 2πtr Ans . T ( a ) We can check the validity of this result by applying the torsion formula . In this case , using Eq . 5-9 , we have п J = = ( r1 = r ; } ) 2 = = ( x2 + r } ) ( r2 = r2 ) Tmax TM ...
... Applying Eq . 5-18 gives T T = Tavg 2tAm 2πtr Ans . T ( a ) We can check the validity of this result by applying the torsion formula . In this case , using Eq . 5-9 , we have п J = = ( r1 = r ; } ) 2 = = ( x2 + r } ) ( r2 = r2 ) Tmax TM ...
Page 687
... Applying Eq . 13-20 yields Ост = T2E , ( KL / r ) 2 = π2E , ( 80 ) 2 = 1.542 ( 10-3 ) E , ( 1 ) First we will assume that the critical stress is elastic . From Fig . 13-22 , E = 150 MPa 0.001 = 150 GPa Thus , Eq . 1 becomes σer 1.542 ...
... Applying Eq . 13-20 yields Ост = T2E , ( KL / r ) 2 = π2E , ( 80 ) 2 = 1.542 ( 10-3 ) E , ( 1 ) First we will assume that the critical stress is elastic . From Fig . 13-22 , E = 150 MPa 0.001 = 150 GPa Thus , Eq . 1 becomes σer 1.542 ...
Common terms and phrases
allowable shear stress aluminum angle of twist Applying Eq average normal stress axes axial force axial load beam's bolt buckling caused centroid column compressive computed constant cross section cross-sectional area deflection deformation Determine the maximum diameter distributed load elastic curve element Example factor of safety free-body diagram ft Prob Hooke's law inē inertia kip/ft kN·m kN/m length linear-elastic loading shown located material maximum bending stress maximum in-plane shear maximum shear stress modulus of elasticity Mohr's circle moment of inertia neutral axis normal strain plane stress plastic principal stresses radius reactions sectional area segment shaft shear flow shear force shear strain shown in Fig SOLUTION Solve Prob statically indeterminate steel strain energy stress acting stress at points stress components stress distribution stress-strain diagram thickness Tmax torque torsional tube vertical yield zero ΕΙ