## Mechanics of Materials |

### From inside the book

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Page 582

Due to the roller and pin supports, the displacement at B and D must be

Within the region of negative moment, AC, Fig. 12-36, the elastic curve must be

concave downward, and within the region of positive moment, CD, the elastic

curve ...

Due to the roller and pin supports, the displacement at B and D must be

**zero**.Within the region of negative moment, AC, Fig. 12-36, the elastic curve must be

concave downward, and within the region of positive moment, CD, the elastic

curve ...

Page 586

For example, if the beam is supported by a roller or pin (1, 2, 3, 4), then it is

required that the displacement be

supports are located at the ends of the beam (1, 2), the internal moment in the

beam must ...

For example, if the beam is supported by a roller or pin (1, 2, 3, 4), then it is

required that the displacement be

**zero**at these points. Furthermore, if thesesupports are located at the ends of the beam (1, 2), the internal moment in the

beam must ...

Page 612

Furthermore, an inflection point or change in curvature occurs where the moment

in the beam (or MIEl) is

determined should be indicated on the curve. Since the moment- area theorems

apply ...

Furthermore, an inflection point or change in curvature occurs where the moment

in the beam (or MIEl) is

**zero**. The unknown displacement and slope to bedetermined should be indicated on the curve. Since the moment- area theorems

apply ...

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### Contents

Contents | 1 |

Strain | 67 |

Mechanical Properties of Materials | 83 |

Copyright | |

16 other sections not shown

### Common terms and phrases

allowable shear stress aluminum angle of twist Applying Eq assumed average normal stress axes axial force axial load beam is subjected beam's bolt buckling caused centroid column compressive computed constant cross section cross-sectional area deflection deformation deter Determine the maximum diameter distributed load Draw the shear elastic curve Example factor of safety free-body diagram Hooke's law inertia internal loadings kip/ft length linear-elastic loading shown material maximum bending stress maximum in-plane shear maximum shear stress modulus of elasticity Mohr's circle neutral axis normal strain plane stress plastic positive principal stresses radius resultant internal sectional area segment shaft shear center shear flow shear force shear strain shown in Fig SOLUTION Solve Prob statically indeterminate steel strain energy stress acting stress at points stress components stress distribution stress-strain diagram tensile tensile stress thickness torque torsional tube vertical yield zero