## Classical Electrodynamics |

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Page 19

... term in the surface integral in (1.42)

GD(x, x') dor' — 1 f q}(x) 3Gd da' (1.44) y ... on G(x, x') seems to be 39s G. 0n'

since that makes the second term in the surface integral in (1.42)

desired.

... term in the surface integral in (1.42)

**vanishes**and the solution is q}(x) –s p(x')GD(x, x') dor' — 1 f q}(x) 3Gd da' (1.44) y ... on G(x, x') seems to be 39s G. 0n'

since that makes the second term in the surface integral in (1.42)

**vanish**, asdesired.

Page 282

(9.64) r op or r With this condition on p it can readily be seen that the integral in (

9.63) over the hemisphere S,

that radius goes to infinity. Then we obtain the Kirchhoff integral for p(x) in region

II: ...

(9.64) r op or r With this condition on p it can readily be seen that the integral in (

9.63) over the hemisphere S,

**vanishes**inversely as the hemisphere radius asthat radius goes to infinity. Then we obtain the Kirchhoff integral for p(x) in region

II: ...

Page 284

... three terms in (9.72), involving the product (GE),

we make use of the following easily proved identities connecting surface

integrals over a closed surface S to volume integrals over the interior of S: Łana, -

s v.

... three terms in (9.72), involving the product (GE),

**vanishes**identically. To do thiswe make use of the following easily proved identities connecting surface

integrals over a closed surface S to volume integrals over the interior of S: Łana, -

s v.

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### Contents

Introduction to Electrostatics | 1 |

BoundaryValue Problems in Electrostatics I | 26 |

BoundaryValue Problems in Electrostatics II | 54 |

Copyright | |

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