## Classical Electrodynamics |

### From inside the book

Results 1-3 of 51

Page 19

42 )

da ' ( 1 . 44 ) For Neumann boundary conditions we must be more careful . The

obvious choice of boundary condition on G ( x , x ' ) seems to be 45 JS CON ( x , x

...

42 )

**vanishes**and the solution is O ( x ) = f ( x ) Gp ( x , x ' ) d®z ' - 1 $ 0 ( x ) OGPda ' ( 1 . 44 ) For Neumann boundary conditions we must be more careful . The

obvious choice of boundary condition on G ( x , x ' ) seems to be 45 JS CON ( x , x

...

Page 282

63 ) over the hemisphere S ,

radius goes to infinity . Then we obtain the Kirchhoff integral for y ( x ) in region II :

is eikR F ¥ ( x ) = - I n Vy + ik ( 1 + y da ' ( 9 . 65 ) KRIR where n is now a unit ...

63 ) over the hemisphere S ,

**vanishes**inversely as the hemisphere radius as thatradius goes to infinity . Then we obtain the Kirchhoff integral for y ( x ) in region II :

is eikR F ¥ ( x ) = - I n Vy + ik ( 1 + y da ' ( 9 . 65 ) KRIR where n is now a unit ...

Page 284

72 ) , involving the product ( GE ) ,

of the following easily proved identities connecting surface integrals over a

closed surface S to volume integrals over the interior of S : $ A : n da = V . A dox $

( n x ...

72 ) , involving the product ( GE ) ,

**vanishes**identically . To do this we make useof the following easily proved identities connecting surface integrals over a

closed surface S to volume integrals over the interior of S : $ A : n da = V . A dox $

( n x ...

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### Contents

Introduction to Electrostatics | 1 |

References and suggested reading | 50 |

Multipoles Electrostatics of Macroscopic Media | 98 |

Copyright | |

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