## The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh and Twelfth |

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Page 14

But if one of the vertices , as D , be within the other triangle ACB ;

But if one of the vertices , as D , be within the other triangle ACB ;

**produce**AC , AD to E , F. + Hyp . therefore , because AC is equalt to AD in the triangle ACD , the E F angles ECD , FDC upon the other side of the base CD are equal ... Page 17

Let AB bé the given straight line , which may be

Let AB bé the given straight line , which may be

**produced**to any length both ways , and let C be a point withс out it . It is required to draw a straight line perpendicular to AB from the point C. AF GB Take any point D upon the * 10 . Page 21

If one side of a triangle be

If one side of a triangle be

**produced**, the exterior angle is greater than either of the interior opposite angles .. Let ABC be a triangle , and let its side BC be**produced**to D : the exterior angle ACD shall be greater than either of ... Page 22

**Produce**BC to D ; and beА cause ACD is the exterior angle of the triangle ABC , * 16 1. AČD is greater * than the interior and opposite angleABC ; to each of these add the angle B ACB ; therefore the angles + 4 Ax . ACD , ACB are ... Page 23

Let ABC be a triangle : any two sides of it together shall be greater than the third side , viz . the sides BA , AC greater than the side BC ; and AB , BC greater than AC ; and BC , CA greater than AB .

Let ABC be a triangle : any two sides of it together shall be greater than the third side , viz . the sides BA , AC greater than the side BC ; and AB , BC greater than AC ; and BC , CA greater than AB .

**Produce**BA to the point ...### What people are saying - Write a review

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The Elements of Euclid: Viz. The First Six Books, Together With the Eleventh ... Euclid Euclid No preview available - 2018 |

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altitude angle ABC angle BAC base base BC BC is equal centre circle ABCD circumference common cone Const contained cylinder demonstrated described diameter divided double draw drawn equal angles equiangular equilateral equimultiples extremities fall figure fore four fourth given given straight line greater half inscribed join less Let ABC likewise magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism PROB produced PROP proportionals proved pyramid ratio reason rectangle contained rectilineal figure remaining angle right angles segment shown sides similar solid solid angle solid parallelopiped sphere square taken THEOR third touches triangle ABC vertex wherefore whole