Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let AC, CF be equiangular parallelograms, having the angle BCD equal to the angle ECG ; the ratio of the parallelogram AC to the parallelogram CF,... Elements of Plane Geometry According to Euclid - Page 139by Andrew Bell - 1837 - 240 pagesFull view - About this book
| Euclid, Isaac Todhunter - Euclid's Elements - 1883 - 428 pages
...having the angle BCD equal to the angle ECO: the parallelogram AC shall have to the parallelogram CF the ratio which is compounded of the ratios of their sides. Let BC and CG be placed in a straight line ; therefore DC and CE are also in a straight line; [I. 14. complete... | |
| Euclid - Geometry - 1890 - 442 pages
....-. AB : CD = LM : NO. 272 Proposition 23. THEOREM — Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let ABCD, CEFG be equiang. Os, in which AA BCD = EGG. Place them so that a pair of the lines BC, CG forming... | |
| Edward Mann Langley, W. Seys Phillips - 1890 - 538 pages
...assumed, and to demonstrate it. PROPOSITION 23. THEOREM. Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let AC, CF be equiangr. ||gms such that L BCD= L ECG ; then ||gm AC : jgm CF in the ratio compounded of... | |
| Edinburgh Mathematical Society - Electronic journals - 1899 - 340 pages
...(EF : GH)2 AB :CD = EF : GH EUCLID VI. 23. Mutually equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let parallelogram BE be equiangular to parallelogram CD, and let _ to prove / / / .|pBE:||-CD = (AB:AC)(AE:AD).... | |
| Edinburgh Mathematical Society - Electronic journals - 1900 - 410 pages
...= (EF :GH)'AB :CD = EF : GH EUCLID VI. 23. Mutually equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let parallelogram BE be equiangular to parallelogram CD, and let _ __ to prove / /I ||™BE:|rOD = (AB:AC)(AE:AD).... | |
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