| 1842
...course) alone are enough to determine its form : or, as Euclid would express it, two triangles which have **two angles of the one equal to two angles of the other,** each to each, have the third angles equal, and all the sides of one in the same proportion to the corresponding... | |
| Chambers W. and R., ltd - 1842
...proposition gives still further information on this useful subject. It shows that if two triangle* have **two angles of the one equal to two angles of the other,** each to each, and one side equal to one aide, namely, either the sides adjacent to the equal angles,... | |
| Encyclopedias and dictionaries - 1842
...course) alone are enough to determine its form : or, as Euclid would express it, two triangles which have **two angles of the one equal to two angles of the other,** each to each, have the third angles equal, and all the sides of one in the same proportion to the corresponding... | |
| Encyclopedias and dictionaries - 1842
...alone are • enough to determine its form : or, as Euclid would express it, two triangles which have **two angles of the one equal to two angles of the other,** each to each, have the third angles equal, and all the sides of one in the same proportion to • the... | |
| John Playfair - Euclid's Elements - 1842 - 317 pages
...: therefore the angle BAC is greatei than the angle EDF. B PROP. XXVI. THEOR. If two triangles have **two angles of the one equal to two angles of the other,** each to each ; and one side equal to one side, viz. either the sides adjacent to the equal angles,... | |
| Euclides - 1845
...and the right angle FCK is equal to the right angle FCL ; therefore, in the two triangles FKC, FLC, **there are two angles of the one equal to two angles of the other,** each to each ; and the side FC, which is adjacent to the equal angles in each, is common to both ;... | |
| Euclid, James Thomson - Geometry - 1845 - 352 pages
...&c. are all equal. Hence (I. 6) CH is equal to HD, DK to KE, &c. Also, in the triangles CHD, DK_E, **there are two angles of the one equal to two angles of the other,** each to each, and (hyp.) the sides CD, DE are equal : therefore (I. 26) the sides CH, HD are equal... | |
| Scottish school-book assoc - 1845
...the side BC is = the side BA, being sides of an equilateral triangle ; .-. the Д» CBD, ABE, have **two angles of the one equal to two angles of the other, and** a side lying between these equal angles also equal ; .-• these triangles are equal in every respect,... | |
| Euclid - Geometry - 1845 - 199 pages
...: and tho angle AEG is equal:f to the angle BEH ; therefore thu triangles AEG, t 15' !• BEH have **two angles of the one, equal to two angles of the other,** each to each, and the sides AE, EB, adjacent to the equal angles, equal to one another ; wherefore... | |
| Euclid, John Playfair - Euclid's Elements - 1846 - 317 pages
...: therefore the angle BAC is greater than the angle EDF. B PROP. XXVI. THEOR. If two triangles have **two angles of the one equal to two angles of the other,** each to each ; and one side equal to one side, viz. either the sides adjacent to the equal angles,... | |
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